Ficar em uma barreira durante um jogo de futebol pode ser muito perigoso, pois o impacto da bola sobre o defensor, que acaba por comprimi-la, pode machucar.
Na figura abaixo a bola sofreu uma redução de 20% em seu volume, a temperatura permaneceu constante igual a 22oC, e a pressão inicial da bola era 2,0 atm. O ar no interior da bola tem caracte-
(Disponível em: https://bityli.com/brSrOy). Adaptada.
Nessas condições, a pressão da bola, medida em atm, é igual a
- A) 0,2
- B) 0,8
- C) 2,0
- D) 2,5
Resposta:
Since the question was annulled and does not have a correct answer, I will explain the concept related to the question.
The question is related to thermodynamics, specifically the ideal gas law. The ideal gas law states that:
$$PV=nRT$$
where $P$ is the pressure of the gas, $V$ is the volume of the gas, $n$ is the number of moles of gas, $R$ is the gas constant, and $T$ is the temperature in Kelvin.
In this case, we are given that the volume of the ball decreases by 20%, the temperature remains constant at 22°C, and the initial pressure of the ball is 2.0 atm. We can use the ideal gas law to find the new pressure of the ball.
First, we need to find the new volume of the ball. Since the volume decreased by 20%, the new volume is:
$$V_{new}=V_{initial}times(1-0.20)=V_{initial}times0.80$$
Since the temperature remains constant, we can use the ideal gas law to find the new pressure:
$$P_{new}V_{new}=nRT$$
$$P_{new}=frac{nRT}{V_{new}}=frac{nRT}{V_{initial}times0.80}$$
Since the initial pressure is 2.0 atm, we can set up the equation:
$$2.0times V_{initial}=nRT$$
Dividing both sides by $V_{initial}$, we get:
$$2.0=nRtimesfrac{T}{V_{initial}}$$
Now, we can find the new pressure:
$$P_{new}=frac{nRT}{V_{initial}times0.80}=frac{2.0}{0.80}=boxed{2.5 atm}$$
Therefore, if the question were not annulled, the correct answer would be 2.5 atm.
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