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Dois corpos tiveram suas temperaturas registradas por termômetros diferentes, sendo um deles graduado na escala Kelvin e o outro na escala Celsius. Em seguida, esses corpos foram colocados em um ambiente cuja temperatura é de 57°C. Ao atingirem o equilíbrio térmico com o ambiente o corpo cuja temperatura havia sido registrada na escala Kelvin apresentou um aumento de 10% no valor de sua temperatura e o outro corpo cuja temperatura havia sido registrada na escala Celsius apresentou uma redução na sua temperatura de 62%. A diferença de temperatura apresentada inicialmente por esses corpos expressa na escala Celsius corresponde a:

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Resposta:

Let's break down the problem step by step. We have two bodies with temperatures measured in different scales: one in Kelvin and the other in Celsius. After being placed in an environment with a temperature of 57°C, they reached thermal equilibrium. The body whose temperature was measured in Kelvin showed a 10% increase in its temperature, and the other body showed a 62% decrease in its temperature.

To find the initial temperature difference between the two bodies in Celsius, we need to convert the Kelvin temperature to Celsius. Let's call the initial temperature of the body measured in Kelvin "T_K" and the initial temperature of the body measured in Celsius "T_C". We know that T_K increased by 10%, so the new temperature is 1.1T_K. Since T_K is in Kelvin, we can convert it to Celsius using the formula T_C = T_K - 273.15. After reaching thermal equilibrium, both bodies have the same temperature, which is 57°C.

Now, let's analyze the body whose temperature was measured in Celsius. Its temperature decreased by 62%, so the new temperature is 0.38T_C. Since this body also reached thermal equilibrium with the environment, its new temperature is also 57°C. Setting up an equation, we get:

$$0.38T_C = 57$$

Solving for T_C, we get:

$$T_C = frac{57}{0.38} = 150°C$$

Now that we have found T_C, we can find the initial temperature difference between the two bodies in Celsius. We know that T_K increased by 10%, so the initial temperature difference is:

$$T_K - T_C = T_C - frac{T_C}{1.1} = 150 - frac{150}{1.1} = 123°C$$

Therefore, the correct answer is option C) 123°C.

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