Pedro mantém uma dieta de 3 000 kcal diárias e toda essa energia é consumida por seu organismo a cada dia. Assim, ao final de um mês (30 dias), seu organismo pode ser considerado como equivalente a um aparelho elétrico que, nesse mês, tenha consumido

Let's break down the problem step by step. Pedro's daily energy intake is 30,000 kcal. To find the equivalent energy consumption in kW·h, we need to convert the energy from kcal to Joules (J) and then to kW·h.

First, let's convert 30,000 kcal to J:

1 kcal = 4.184 J, so

30,000 kcal = 30,000 × 4.184 J = 125,520 J

Now, let's convert the energy from J to kW·h:

1 kW·h = 3,600,000 J, so

125,520 J ≈ 125,520 / 3,600,000 kW·h ≈ 0.035 kW·h

Since Pedro consumes this energy in 1 day (24 hours), we can find the equivalent power (P) in kW:

P = Energy / Time = 0.035 kW·h / 24 h ≈ 0.00146 kW

Now, let's find the total energy consumed in 30 days:

Energy = Power × Time = 0.00146 kW × 720 h (30 days) ≈ 1.0512 kW·h

Therefore, the correct answer is C) 100 kW·h, which is the closest value to our calculated result.

It's essential to understand that the problem is asking for the total energy consumed in 30 days, not the daily energy intake. By converting the energy from kcal to J and then to kW·h, we can find the equivalent power consumption and finally calculate the total energy consumed in 30 days.